在计时器在python中用尽之前完成一项任务

Question

I have 2 functions, one is a countdown timer and another is basically the function that I want to execute within the time period.

My code for the countdown timer is as follows:

def countdown(count):
   while count > 0:
       print(count)
       count -= 1
       time.sleep(1)
   return

My other function that I want to complete its execution before the timer runs out is as follows:

def solution(imat, painter):
nrows, ncols = imat.shape # gets the total number of rows and columns from a text file
for r in range(nrows): 
    for c in range(ncols):
        if imat[r,c] == 1: # checks if there is a 1 in any index (row and column) in the text file
            painter.paint('square',r, c, 1) # square is the method it uses to print, i.e  in blocks, and 1 is basically the size of the block that prints 

My question now is that is it possible for me to run the solution function completely before the timer runs out?

I have tried to use t1 = threading.Thread(target=countdown , args =(imat, painter)) in the solution function,, but it did not work. The maximum value count can be set to is 20.

The painter.paint(...) function runs at 160 commands, meaning there are a 160 1s in the text file, there is there is a way to reduce the number of commands that function takes to run?

Can the number of commands be reduced using threads?

All help will be highly appreciated.

Answer 1

It looks like Peter Wood is probably on the money in that you are targeting the countdown function, but passing arguments for the solution function in your threading code.

However, if you simply want to time your code, this guide has some really good stuff in it on how to do so. I personally love the line_profiler as it gives you the execution time of each individual line.