向用户显示他已注销

Question

I want this: If the user logs out(session destroy) then index should say: You are logged out.

if (isset($_SESSION['user']) && $_SESSION['user'] == true) {
echo "Welcome on the users page!, " . $_SESSION['username'] . "!";
    } 
    elseif (!isset($_SESSION['user'])) {
    echo "You logged out..";}

The problem I am having is that it also shows you logged out when you haven't even logged in to be able to log out. I only want it to show if the user logs out.

Also I only want "You are logged out" to show up once. If you refresh the page, it should be gone

Answer 1

That is because of the following condition:

!isset($_SESSION['user']

This is true whether the user logged-in or not. So you have to make some other session variable to check for the user logged out. And that is only set when the user logged out.

Ex:

if( !isset($_SESSION['user'] && isset($_SESSION['logged_out']))
{
    // isset($_SESSION['user'] to check if user logged out and extra condition to check if user comes here after logged-out.
}

and check this on index page.

Answer 2

Instead of using php unset(); function to destroy a session, you can actually save boolean "false" in the $_SESSION["user"];

For example, in you logout page:

Instead of destroying, set session to false

Ex:

`` //When logging out $_SESSION["user"] = false;

//now to check if user logged out

if($_SESSION["user"] === false) {

echo "you logged out";

}elseif(!isset($_SESSION["user"])) {//when the session finally expires
echo " you haven't logged in";

}else{
echo "you are logged in";
}


 //to get rid of it after page reload,    you need to unset the SESSION


unset($_SESSION["user"]);