如何在 Windows 上使用单个命令行编译和运行 Java

Question

Everytime I want to build and run my program I do:

javac myProgram.java
java myProgram

I want to do something like this:

buildrun = javac (some_argument).java && java (some_argument)

so after I can just

buildrun myProgram

How to achieve this on Windows?

Answer 1

As other's have suggested you can simply create a batch file to build and run your program. Copy this in Notepad and save as .bat.

@echo off
set /p class="Enter Class: "
javac "%class%".java
java "%class%"

As you want, the batch file will ask for a FileName when it runs. In your case, you can set it to 'myProgram' and it will then compile and run the program.

Just make sure your batch file and your java file reside in the same folder for this script to run. You can always tweak the bat file to even accept the full path of the Java file.

Answer 2

要在 cmd 中使用单个命令行编译和运行 Java，请使用：java myProgram.java

Answer 3

You can use Makefile this way:

1. Create a file named Makefile within the same folder where your java files reside.
2. Add these contents to Makefile

run: compile
    java $(class)

compile: 
    javac $(class).java

3. From terminal, run this command: make run class=myProgram

This way, it will compile first then run your java class in a single command

Answer 4

Yet another solution. Create buildrun.cmd file with the following code:

@echo off
javac %1.java
if errorlevel = 0 goto RUN

:ERROR
echo "Build fails!"
goto END

:RUN
java %1

:END

Now you can pass the class name which should be processed. For example: buildrun MyProgram to compile MyProgram.java and run MyProgram.class In this case execution will performs only if your class was compiled successful.