[英]Update query using MySQL and Node.js
I am using Node.js with MySQL. 我在MySQL上使用Node.js。 Everything works fine, however I am having issues when using the UPDATE query. 一切正常,但是使用UPDATE查询时出现问题。
My database table looks like this:
id | employeeId
54027 | 8241
63708 | 3421
393835 | 3687
To check for external updates, I am sending a request to an API using the following code: 为了检查外部更新,我正在使用以下代码向API发送请求:
const obj = response.data.map(function(item) {
return { id: item.entryId.id, employeeId: item.employeeId.id };
});
A console.log of this, returns the following: 的console.log返回以下内容:
[ { id: 54027, employeeId: 8242 },
{ id: 63708, employeeId: 3422 },
{ id: 393835, employeeId: 3688 }
]
So, since my API call has returned data which is different than what is in my DB, I want to issue an UPDATE query to MySQL, using the following code: 因此,由于我的API调用返回的数据与数据库中的数据不同,因此,我想使用以下代码向MySQL发出UPDATE查询:
const query = connection.query('UPDATE entries SET employeeID = ? WHERE entrieId = ?', obj,
(error, results, fields) => {
if (error) console.log(error);
else {
console.log('Updated!');
}
});
I get an error saying that I am using the wrong SQL syntax, then I get this at the bottom: 我收到一条错误消息,说我使用了错误的SQL语法,然后在底部显示了此错误:
UPDATE entries SET employeeID =
id = 54027,
employeeId = 8242 WHERE entrieId =
id = 63708,
employeeId = 3422
UPDATE entries SET employeeID =
id = 54027,
employeeId = 8242 WHERE entrieId =
id = 63708,
employeeId = 3422
I have been following tutorials and other advice found on forums / documentation for the best and correct way to issue the UPDATE, and am getting confused by my result. 我一直在遵循在论坛/文档中找到的教程和其他建议,以获取发布UPDATE的最佳和正确方法,并且对我的结果感到困惑。
let query = '';
for(var i = 0, len = obj.length; i < len; i++) {
query += 'UPDATE entries SET employeeID ='+obj[i]['employeeID']+' WHERE entrieId = '+obj[i]['id']+';'
}
connection.query(query,
(error, results, fields) => {
if (error) console.log(error);
else {
console.log('Updated!');
}
});
When formatting SQL queries, JSON objects are turned into key = 'val'
pairs. 格式化SQL查询时,JSON对象会变成key = 'val'
对。 Have a look at https://github.com/mysqljs/sqlstring#escaping-query-values . 看看https://github.com/mysqljs/sqlstring#escaping-query-values 。 Consider the following code, 考虑以下代码,
var data = {email: "e@example.com", status: 2} // consider some dummy data
var formattedQ = SqlString.format("UPDATE users SET ? WHERE id = 34", data);
// formattedQ would be:
"UPDATE users SET `email` = 'e@example.com', `status` = 2 WHERE id = 34"
For your problem you should use an array of values containing employeeId
and id
. 对于您的问题,您应该使用包含employeeId
和id
的值数组。
var data = [8242, 54027] // 8242 is employeeId and 54027 is id.
var q = "UPDATE entries SET employeeID = ? WHERE entrieId = ?";
connection.query(q, data, (err, results, fields) => {
// Your code here
});
// This would execute the following formatted query:
UPDATE entries SET employeeID = 8242 WHERE entrieId = 54027
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