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比较表中的前4个字符和从codeigniter中的数据库中获取数据

[英]Comparing first 4 characters from table and fetching data from database in codeigniter

I have two different tables as testimonial and pagetitles . 我有两个不同的tables作为testimonialpagetitles While fetching the Pagetitles from database . database提取Pagetitles时。 I need to compare first 4 characters if both matches then I should get the data. 我需要比较前4个字符,如果两个匹配,那么我应该得到数据。

function getpagetitle($id)
{

    $this->db->select('P.*,T.testimonial_name');        
    $this->db->from('pagetitle AS P');      
    $this->db->join('testimonials AS T','SUBSTR(T.testimonial_name, 4) = SUBSTR(P.page_title, 4)','INNER');
    $this->db->where(array('P.page_title'=>$id));       
    $q=$this->db->get();        
    //var_dump($this->db->last_query());
    //print_r($q->num_rows());
    if($q->num_rows()>0)
      {
    $output = $q->result();

   return $output[0];
        }
    else
    {
    return false;
    }
}

Database tables 数据库表

testimonials: 推荐:

+----------------+-------------------+-------------+
| testimonial_id |  testimonial_name | client_name |
+----------------+-------------------+-------------+
| 1              |  testimonial      | abc         |
| 2              |  testimonial      | def         |
+----------------+-------------------+-------------+

Pagetitle 页面标题

+--------------+-------------+
| pagetitle_id | pagetitle   |   
+--------------+-------------+
|  1           | testimonial |
|  2           | career      |
+--------------+-------------+

i think you have to use if then statement in mysql , so if we want to change your query , it must be something like this : 我认为你必须在mysql中使用if then语句 ,所以如果我们想要更改你的查询,它必须是这样的:

select P.*,T.testimonial_name from pagetitle AS P , testimonials as T (
 select IF 'SUBSTR(T.testimonial_name, 4) = SUBSTR(P.page_title, 4)'  
 where P.page_title>5
)

i dont test it , but i think it must be true 我不测试它,但我认为它一定是真的

If you do not got any solutions yet try this below code, 如果您还没有任何解决方案,请尝试以下代码,

$testimonials = $this->db->query("SELECT `P`.*, `T`.`testimonial_name` 
FROM (`pagetitle` P) INNER JOIN `testimonials` T ON 
((SUBSTR(`T`.`testimonial_name`, 1, 4)) = (SUBSTR(`P`.`page_title`, 1, 4))) 
WHERE `P`.`page_title` = SUBSTR('{$id}', 1, 4)")->result_array();
print_r($testimonials);
/* Output of $testimonials will be like below:
Array
(
    [0] => Array
        (
            [fieldname_1] => val
            [fieldname_2] => val
        )

    [1] => Array
        (
            [fieldname_1] => val
            [fieldname_2] => val
        )
)
*/
if(count($testimonials) > 0) {
//$output = $testimonials->result();
return $testimonials[0];
} else {
return false;
}

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