在Shell中，如何制作文件数组，以及如何使用它将其与另一个文件进行比较？

Question

How do I make an array of files in shell. Is it just

files = (file1.txt file2.txt file3.txt)

or is it

files = ("file1.txt" "file2.txt" "file3.txt)

If later on in the program I want to refer to this array and pick a specific file to read, how would I do that. I am asking because I would like to have a conditional that would read that file and compare it to an output file.

Would I just do: ( I know I can't do this)

if grep -q ${outputs[i]} output; then
   #etc.

But what should I do instead then?

Answer 1

No spaces around = in assignments, arrays are no excepetion.

files=( file1.txt "file2.txt" )

Quotes around file names are needed if file names contain special characters, eg whitespace, parentheses, etc.

You can use a for loop to walk the array:

for file in "${array[@]}" ; do
    if grep -q "$file" output ; then

Are you sure you want to use $file as the regular expression? Then you need to handle regex characters specially, ie dot, caret, dollar sign, etc.

If you want to compare contents of the two files, use diff , not grep .

if diff -q "$file" output > /dev/null ; then
    echo Same
else
    echo Different
fi