从Notepad ++中删除行中的所有数字+符号

Question

Is it possible to remove every line in a notepad++ Not Containing

a   b   c   d   e   f   g   h   i   j   k   l   m
n   o   p   q   r   s   t   u   v   w   x   y   z

A   B   C   D   E   F   G   H   I   J   K   L   M
N   O   P   Q   R   S   T   U   V   W   X   Y   Z

,   .   '

Like that :

Remove Non-ascii

.*[^\x00-\x7F]+.*

Remove Numbers

.*[0-9]+.*

---

Text :

example
example'
example,
example.


example123
éxample è
[example/+
example'/é,
example,*
exa'mple--
example@
example"

Answer 1

You may use

^(?![a-zA-Z,.']+$).+$\R?

The regex matches any non-empty line ( .+ ) that does not only consist of ASCII letters, , , . or ' . \\R? at the end matches an optional line break.

Details :

• ^ - start of a string
• (?![a-zA-Z,.']+$) - a negative lookahead that fails the match if its pattern is not matched: [a-zA-Z,.']+ - 1 or more ASCII letters, comma, period or single quote up to the end of the line ( $ )
• .+ - 1+ chars other than line break char
• $ - end of a line
• \\R? - an optional line break char (sequence)

Answer 2

You can remove them like this:

Find what: ^.*[^a-zA-Z.,'].*$
Replace with: ``

Explanation:

• .* for any text
• the negated character class [^...] for any unwanted character
• then again .* for more any text
• You need to wrap it into ^...$ to match the whole line

If you want to delete the linefeed characters, then you can use \\r?\\n instead of the $ sign. Ie: ^.*[^a-zA-Z.,'].*\\r?\\n

Answer 3

尝试替换所有这些匹配

^.+?[^a-zA-Z,.'\r\n]+(.|\r?\n)