'else'的语法错误，无法找出问题

Question

I started Python yesterday and practiced making small scripts but none of them end up working. I somewhat get the basics but I just feel so stupid and frustrated. Here's one of the scripts.

UserInput = input("Enter")
if UserInput == "yes":
print ("good job")
elif  print ("wrong"):
else:
   return

Answer 1

There are 3 problems with the code. The first one is proper indentation. If your code doesn't look like below, use [tab]* to fix it. For the other problems see comments in the code:

UserInput = input("Enter")
if UserInput == "yes":
    print ("good job")
# elif requires a condition to evaluate. It's a shorthand for else if 
# you can do e.g. elif UserInput == "no"
elif (condition): # colon goes here
    print ("wrong")
else:
    return

Programming requires precise syntax. When you start programming, identifying these small nuisances is difficult. Keep trying. It will become automatic.

*actually you should use 4 spaces, see comment below by Matthias. I personally have my IDE configured to insert 4 spaces when I press [tab].

Answer 2

this should help. I didn't exactly get what you wanted to do with the elif part , so in this code if and only if the input is yes then it will execute the if condition , otherwise would always execute the else condition.

PS :- It would be good if you can clarify what exactly you want .

UserInput = raw_input("Enter :- ")
if UserInput == "yes":
    print ("good job")
else:
    print ("wrong")

Answer 3

elif must specify a condition and indentation must be consistent throughout the module:

UserInput = input("Enter")
if UserInput == "yes":  
    print ("good job")  # <-+
elif True or False:     #   |   elif needs a condition as well
    print ("wrong"):    # <-+-- indentation must be indentical
else:                   #   |
    return              # <-+

Answer 4

Check your indentation

UserInput = input("Enter")
if UserInput == "yes":
  print ("good job") 
else:
   print ("wrong")
   return