在python3中打开多个txt文件

Question

I have multiple txt files with similar names as follow: item1.txt, item2.txt, item3.txt,

item700.txt what is the best way to read these files' data in using python? Thank you in advance

Answer 1

Use range() function to iterate over the 700 integers:

import os
import io

work_dir = "path/to/workdir"

for index in range(1, 701):
    name = "item{index}.txt".format(index=index)
    path = os.path.join(work_dir, name)
    with io.open(path, mode="r", encoding="utf-8") as fd:
        content = fd.read()

A different way is to use glob.glob function to search for the text files:

for path in glob.glob(os.path.join(work_dir, "item*.txt")):
    with io.open(path, mode="r", encoding="utf-8") as fd:
        content = fd.read()

Answer 2

Assuming all and only the text-files are in a Folder

import os 

all_txt_files = os.listdir(file_dir)

for txt in all_txt_files:
    txt_dir = file_dir + txt    
    with open(txt_dir, 'r') as txt_file:

    # read from a single Textfile whatever you want to

Note: Depending on your python version the Textfiles might not be sorted by os.listdir() prevent that by sorted(os.listdir())