SQL-根据另一列中的条件在一个列中选择不同的记录

Question

I understand there are similar questions but I haven't found one that discusses this yet...

Example Sales table. Need to return Name of individual who did not sell product type 'A' on 21-Feb-16

Name        Date            Product Type
John        21-Feb-16       A
John        21-Feb-16       B
Joe         21-Feb-16       D
Joe         21-Feb-16       B
Jane        21-Feb-16       A
Jane        21-Feb-16       D

Desired return:

Name        
Joe 

Need something more than just...

select 
distinct Name
from Sales
where Name = 'Joe'

Answer 1

just read about Not in

select *
from Sales
where Name not in 
(select name
from Sales
where Date='21-Feb-16'
and product_type='A')

Answer 2

If you have a table like SalesPerson ; using not exists() :

select Name
from SalesPerson sp
where not exists (
  select 1
  from Sales s
  where s.SalesPersonId = sp.SalesPersonId
    and s.ProductType = 'A'
    and s.date = '20160221' 
  )

otherwise:

select distinct Name
from Sales s
where not exists (
  select 1
  from Sales i
  where s.Name = i.Name
    and i.ProductType = 'A'
    and i.date = '20160221'
  )

Answer 3

You could use the EXCEPT operator for this.

SELECT DISTINCT Name
FROM Sales
EXCEPT
SELECT Name
FROM Sales
WHERE ProductType = 'A' AND Date = '21-Feb-16'

Answer 4

You can use the NOT in and a subselect like the following. In practical way you retrieve all the sellers excluding the sellers who sold at least one product of type A

select distinct 
    Name
from 
    Sales
where 
    Name not in (select distinct Name
                 from Sales
                 where Product_type = 'A' and date '21-feb-2016')

Answer 5

How about using:

select 
Name
from Sales
where Name = 'Joe'
group by Name