在Linux中使用管道日期grep

Question

I wanted to filter my date command in Linux by not having the Days printed out. So I tried to do something like this in the Linux terminal (for example):

date | grep -v 'Tuesday'

But, it didn't work . It prints nothing. Is this normal or did I make a mistake or something?

Answer 1

Date can print in almost any format you want. To print the date and time without the day of the week:

$ date '+%D %r'
05/17/17 02:09:22 PM

+%D %r describes the format. There are many possible formats. See man date for details.

The pipeline command

date | grep -v 'Tuesday'

This does not remove the days. It removes any line that contains the string Tuesday . Examples:

$ date
Wed May 17 14:14:12 PDT 2017
$ date | grep -v 'Wed'
$ date | grep -v 'Thu'
Wed May 17 14:14:20 PDT 2017