从AJAX发送PHP变量

Question

I am creating a notification checker through AJAX and PHP.

I have created an alert which is "yep" or "nope" to depend if the response is received, however neither alert is showing.

Am I sending my php variable correctly?

PHP:

 <?php session_start(); if($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest') { //Request identified as ajax request //HTTP_REFERER verification if($_SESSION['email'] == $_GET['email']) { require_once 'connect.php'; /* FORM VARIABLES */ $email = strtolower($_GET['email']); try { $stmt = $pdo->prepare("SELECT * FROM notifications WHERE to=:email"); $stmt->execute(array(":email"=>$email)); $count = $stmt->rowCount(); echo $count; } catch(PDOException $e){ echo $e->getMessage(); } } else { header('Location: http://website.com'); } } else { header('Location: http://website.com'); } ?> 

AJAX:

  <script> function notificationCheck() { $.ajax({ url: 'website.com/page.php?email='<? echo $email ?>, data: "", success: function (data) { var bubification = data; if (bubification === 0) { window.alert("Yes"); } else { window.alert("Nope"); } $('#profile-sidebar-responsive-notifcation-count').html(''+bubification+''); $('#profile-sidebar-notifcation-count').html(''+bubification+''); } }); } $(document).ready(notificationCheck); setInterval(notificationCheck, 10000); </script> 

Answer 1

在您的ajax URL中，您缺少php

Answer 2

Try this one. I see a sytax error in url. To concatenate a string in php you use . and in jquery you use + . You haven't concatenated your string with php blocks in url

$.ajax({
    url: 'website.com/page.php?email='+'<?php echo $email ?>',          
    method: "GET",
    success: function (data) {

    var bubification = data;

    if (bubification === 0) {

    window.alert("Yes");

    } else {

    window.alert("Nope");

    }
    $('#profile-sidebar-responsive-notifcation-count').html(''+bubification+'');                        $('#profile-sidebar-notifcation-count').html(''+bubification+'');
    }
});

Answer 3

我认为您有串联错误更改

<? echo $email ?> to +'<?php echo $email ?>' 

Answer 4

In PHP if you handling AJAX you are suppose to echo the response always

please remove header('Location: http://website.com'); and use something like

 echo 'false'

Because if your $email is not matching you are sending that call to another page.