Python 3.x-如何在两个字符串中查找字符集的交集

Question

This is the code I am trying to edit but I do not know how:

var1= 'ABC'
var2= 'DBC'
match= any(x in var1 for x in var2)
if any(x in var1 for x in var2):
    print("var1 in var2")
    print("The letters that are in var1 and var2 are", match)
else:
    print("No results.")

When I run that code I get these results that are useless for me:

var1 in var2
The letters that are in var1 and var2 are True

What I want the program to do is to:

var1 in var2
The letters that are in var1 and var2 are BC

If were to change var1 to ABD I want the result to be:

var1 in var2
The letters that are in var1 and var2 are BD

PS I also want it to print the letters in alphabetical order: So I want the result to be like The letters that are in var1 and var2 are BD , and not The letters that are in var1 and var2 are DB .

Thank you very much. Your sincerely.

Answer 1

var1= 'ABC'
var2= 'DBC'
match= [x for x in var1 if x in var2]
if match:
    print("var1 in var2")
    match_str = ''.join(sorted(match))
    print("The letters that are in var1 and var2 are %s." % match_str)
else:
    print("No results.")

This prints:

var1 in var2
The letters that are in var1 and var2 are BC.

Basically I'm using a list comprehension to find which elements are the same, checking if the list is non-empty with if match , sorting using the sorted function, and then concatenating each element into a single string with ''.join (joining with empty string '' because we don't want spaces between the letters).

Then, to avoid having commas in the output, I use % format syntax to insert the sorted characters into the output sentence.

Answer 2

You can also use set arithmetic to do this.

>>> var1 = 'ABC'
>>> var2 = 'DBC'
>>> ''.join(set(var1).intersection(set(var2)))
'CB'

Changing var1 ,

>>> var1 = 'ABD'
>>> ''.join(set(var1).intersection(set(var2)))
'BD'