[英]How to build a tensor from 2 scalars in Tensorflow?
I have two scalars resulting from the following operations: a = tf.reduce_sum(tensor1)
, b = tf.matmul(tf.transpose(tensor2), tensor3)
this is a dot product since tensor2
and tensor3
have the same dimensions (1-D vectors). 我通过以下操作得到两个标量:
a = tf.reduce_sum(tensor1)
, b = tf.matmul(tf.transpose(tensor2), tensor3)
这是一个点积,因为tensor2
和tensor3
具有相同的尺寸(1- D个向量)。 Since these tensors have shape [None, dim1]
it becomes difficult to deal with the shapes. 由于这些张量具有形状
[None, dim1]
因此很难处理这些形状。
I want to build a tensor that has shape (2,1) using a
and b
. 我想使用
a
和b
构建具有形状(2,1)的张量。
I tried tf.Tensor([a,b], dtype=tf.float64, value_index=0)
but raises the error 我尝试了
tf.Tensor([a,b], dtype=tf.float64, value_index=0)
但引发了错误
TypeError: op needs to be an Operation: [<tf.Tensor 'Sum_5:0' shape=() dtype=float32>, <tf.Tensor 'MatMul_67:0' shape=(?, ?) dtype=float32>]
Any easier way to build that tensor/vector? 有没有更简单的方法来构建张量/向量?
This would do probably. 这可能会做到。 Change axis based on what you need
根据需要更改轴
a = tf.constant(1)
b = tf.constant(2)
c = tf.stack([a,b],axis=0)
Output: 输出:
array([[1],
[2]], dtype=int32)
You can use concat or stack to achieve this: 您可以使用concat或stack来实现此目的:
import tensorflow as tf
t1 = tf.constant([1])
t2 = tf.constant([2])
c = tf.reshape(tf.concat([t1, t2], 0), (2, 1))
with tf.Session() as sess:
print sess.run(c)
In a similar way you can achieve it with tf.stack
. 以类似的方式,您可以使用
tf.stack
来实现。
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