[英]How to sort items to display by using Bootstrap's Dropdown menu
I have an app that displays recipes on the index page (mywebsite.com/recipes). 我有一个在索引页面(mywebsite.com/recipes)上显示食谱的应用程序。 I want to sort them either by date or by popularity, and have a button directly on the page so the user can choose how he wants to sort the recipes.
我想按日期或受欢迎程度对它们进行排序,并直接在页面上有一个按钮,以便用户可以选择他想对食谱进行排序的方式。 I am using bootstrap's dropdown menu, which uses anchor tags (would a select menu be better suited?).
我正在使用引导程序的下拉菜单,该菜单使用锚标记(选择菜单更适合吗?)。
Here's the dropdown menu: 这是下拉菜单:
<div class="dropdown indexDropdown">
<button class="btn btn-default dropdown-toggle" type="button" id="dropdownMenu1" data-toggle="dropdown" aria-haspopup="true" aria-expanded="true">
Sort by
<span class="caret"></span>
</button>
<ul class="dropdown-menu" aria-labelledby="dropdownMenu1">
<li><a href="#(WHAT SHOULD I PUT HERE)">Most recent</a></li>
<li><a href="#(WHAT SHOULD I PUT HERE)">Most popular</a></li>
</ul>
</div>
Here's the route I want to use when "Date" is chosen or when nothing is clicked by the user (default sort): 这是选择“日期”或用户未单击任何内容时要使用的路线(默认排序):
//INDEX ROUTE (SORT BY DATE)
router.get("/WHAT SHOULD I PUT HERE", function(req, res){
if(req.query.search && req.xhr) {
const regex = new RegExp(escapeRegex(req.query.search), 'gi');
// Get all recipes from DB
Recipe.find({title: regex}).limit(9).sort({"createdAt": -1}).exec(function(err, foundRecipes){
if(err){
console.log(err);
} else {
res.status(200).json(foundRecipes);
}
});
} else {
// Get all recipes from DB if no search input
Recipe.find({}).sort({"createdAt": -1}).limit(9).exec(function(err, foundRecipes){
if(err){
console.log(err);
} else {
if(req.xhr) {
res.json(foundRecipes);
} else {
res.render("recipes/index",{recipes: foundRecipes});
}
}
});
}
});
Here's the route I want to use when "Popularity" is chosen or when nothing is clicked by the user (default sort): 这是选择“人气”或用户未单击任何内容时要使用的路线(默认排序):
//INDEX ROUTE (SORT BY POPULARITY)
router.get("/WHAT SHOULD I PUT HERE", function(req, res){
if(req.query.search && req.xhr) {
const regex = new RegExp(escapeRegex(req.query.search), 'gi');
// Get all recipes from DB
Recipe.find({title: regex}).limit(9).sort({"createdAt": -1}).exec(function(err, foundRecipes){
if(err){
console.log(err);
} else {
res.status(200).json(foundRecipes);
}
});
} else {
// Get all recipes from DB if no search input
Recipe.find({}).sort({"numberOfPins": -1}).limit(9).exec(function(err, foundRecipes){
if(err){
console.log(err);
} else {
if(req.xhr) {
res.json(foundRecipes);
} else {
res.render("recipes/index",{recipes: foundRecipes});
}
}
});
}
});
How should I do this? 我应该怎么做? What href should I assign to each anchor tag in the dropdown menu?
我应该在下拉菜单中为每个锚标记分配什么href? Should I just add something like href="/recipes?_sort=POPULARITY"?
是否应该添加href =“ / recipes?_sort = POPULARITY”之类的内容?
Thanks a lot! 非常感谢!
<a href='/route1'></a>
creates a get request for route1. <a href='/route1'></a>
创建对<a href='/route1'></a>
的获取请求。 So I created two separate routes (route1 and route2) for sorting mongo data. 因此,我创建了两个单独的路由(route1和route2)来对mongo数据进行排序。
<a href='/route1'>Sort by Popularity</a>
<a href='/route2'>Sort by Date</a>
router.get("/route1",function(){
Sort data by popularity
})
router.get("/route2",function(){
Sort data by Date
})
Works for me. 为我工作。 May not be an optimum method but it just works
可能不是最佳方法,但它确实有效
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