[英]Java8 Stream - HashSet of Byte from IntStream
I'm trying to create a HashSet<Byte>
of byte
s 1, 2, 3, ... 9
with the Java 8 Streams API. 我正在尝试使用Java 8 Streams API创建byte
s 1, 2, 3, ... 9
的HashSet<Byte>
。 I thought using IntStream
and then downgrading the values to byte
would do it. 我想使用IntStream
,然后将值降级为byte
就可以了。
I'm trying variations of 我正在尝试变种
HashSet<Byte> nums = IntStream.range(1, 10).collect(Collectors.toSet());
HashSet<Byte> nums = IntStream.range(1, 10).map(e -> ((byte) e)).collect(Collectors.toSet());
But none of those work. 但这些都不起作用。
Error:(34, 73) java: method collect in interface java.util.stream.IntStream cannot be applied to given types;
required: java.util.function.Supplier<R>,java.util.function.ObjIntConsumer<R>,java.util.function.BiConsumer<R,R>
found: java.util.stream.Collector<java.lang.Object,capture#1 of ?,java.util.Set<java.lang.Object>>
reason: cannot infer type-variable(s) R
(actual and formal argument lists differ in length)
Do I need to do flatMap
or mapToObject
? 我需要做flatMap
或mapToObject
吗?
You need to use mapToObj since HashSet and all generics require Objects 您需要使用mapToObj,因为HashSet和所有泛型都需要对象
Set<Byte> nums = IntStream.range(1, 10)
.mapToObj(e -> (byte) e)
.collect(Collectors.toSet());
You could use a MutableByteSet
from Eclipse Collections with the IntStream
and avoid the boxing. 你可以使用一个MutableByteSet
从Eclipse的收藏与IntStream
和避免装箱。
ByteSet byteSet = IntStream.range(1, 10)
.collect(ByteSets.mutable::empty,
(set, i) -> set.add((byte) i),
MutableByteSet::addAll);
Note: I am a committer for Eclipse Collections 注意:我是Eclipse Collections的提交者
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