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Groovy:正则表达式过滤掉“ Key:Value”对并存储在数组中

[英]Groovy: regex to filter out “Key:Value” pair and store in an array

I am writing a GROOVY script for a Jenkinsfile to do following: 我正在为Jenkinsfile编写GROOVY脚本,以执行以下操作:

Step-1: read the input file info_file.txt . 步骤1:读取输入文件info_file.txt Contents of info file are as under: 信息文件的内容如下:

sh> cat info_file.txt
CHIP_DETAILS:1234-A0;1456-B1;2456-B0;3436-D0;4467-C0

Step-2: Store the CHIP_DETAILS in an array after removing the suffix -A0,-B1 etc.. 步骤2:删除后缀-A0,-B1等后,将CHIP_DETAILS存储在数组中。

for example: 例如:

Integer[] testArray = ["1234", "1456", "2456" , "3436" , "4467"]

Step-3: print the elements of the array sequentially. 步骤3:依序列印阵列中的元素。 For example: 例如:

testArray.each {
println "chip num is ${it}"
}

I have written a small code to test if the CHIP_DETAILS 'key' is present in the input file and it is working. 我编写了一个小代码来测试CHIP_DETAILS '是否存在于输入文件中并且可以正常工作。 However i'm finding it difficult to write the regex for removing the suffix ( -A0,-B1 etc..) and storing the corresponding value in an array. 但是,我发现很难编写用于删除后缀( -A0,-B1等)并将正则表达式存储在数组中的正则表达式。 the code is as under: 代码如下:

stage('Read_Params') 
        { 
            steps 
            {
                script
                {
                    println ("Let's validate and see whether the "Key:Value" is present in the info_file.txt\n");
                    if ( new File("$JobPath/Inputparams.txt").text?.contains("CHIPS_DETAILS"))
                    {
                       println ("INFO: "Key:Value" is present in the info_file.txt \n");
                      >>>>> proceed with Step-1, Step-2 and Step-3... <<<<< 
                    }
                    else 
                    {
                       println ("WARN: "Key:Value" is NOT present in the info_file.txt  \n");
                       exit 0;
                    }
                }
            }   
        }

Thanks in advance for help! 在此先感谢您的帮助!

You could try something like the following: 您可以尝试以下操作:

def chipDetails = 'CHIP_DETAILS:1234-A0;1456-B1;2456-B0;3436-D0;4467-C0'

def testArray = ( chipDetails =~ /(?<=^|[:;])\d*(?=[-])/)​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​
assert​ '1234' == testArray[0]
assert '1456' == testArray[1]
assert '2456' == testArray[2]
assert '3436' == testArray[3]
assert '4467' == testArray[4]​

The regular expression ensures the number you're trying to capture is either at the start of a line or prefixed with : or ; 正则表达式可确保您尝试捕获的数字位于行的开头或以:或;为前缀 and suffixed with - 并以-结尾

There can be any amount of digits between the delimiters. 分隔符之间可以有任意数量的数字。

Iterate over the results like: 遍历以下结果:

testArray.each{
    println it
}​

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