如何使用Newtonsoft.JSON JObject获得一致的日期时间值

Question

I have a ASP.Net Core service that uses Newtonsoft.Json library for working with JSON data. The sample JSON input has a string that holds a date value in ISO8601 format. However I am observing different date time value being returned for an equivalent date. Here is the sample code -

    var jsonString = @"{
        ""data"": {
            ""name"": ""John Doe"",
            ""dateOfBirth"": ""1990-05-25T15:54:49.119+00:00""
        }
    }";

    var jsonObj = JObject.Parse(jsonString);
    var person = jsonObj.ToObject<Person>();

    DateTime dateOfBirth = DateTime.Parse(person.Data.DateOfBirth);
    if (dateOfBirth.Kind != DateTimeKind.Utc)
    {
        dateOfBirth = dateOfBirth.ToUniversalTime();
    }
    Console.WriteLine("Date of birth is " + dateOfBirth.ToString("o"));

The Person class is like this -

class Person
{
    public PersonalData Data;
}

class PersonalData
{
    public  string Name { get; set; }
    public string DateOfBirth { get; set; }
}

If I provide ""dateOfBirth"": ""1990-05-25T15:54:49.119+00:00 "", the output is -

Date of birth is 1990-05-25T15:54:49.0000000Z

If I provide ""dateOfBirth"": ""1990-05-25T15:54:49.119Z"" , the output is -

Date of birth is 1990-05-25T10:24:49.0000000Z

As it can be seen, the output is different where as it should have been same. The callers can set any date time string in ISO8601 format.

Is there any way where this can be handled consistently?

Answer 1

This is because DateTime.Parse() takes into account the system time zone (of the computer you run this code)

The solution is here

   var jsonString = @"{
        ""data"": {
            ""name"": ""John Doe"",
            ""dateOfBirth"": ""1990-05-25T15:54:49.119+00:00""
        }
    }";
var jsonObj = JObject.Parse(jsonString);
var person = jsonObj.ToObject<Person>();

var dateTimeOffset = DateTimeOffset.Parse(person.Data.DateOfBirth, CultureInfo.InvariantCulture);
DateTime dateOfBirth = dateTimeOffset.UtcDateTime;
Console.WriteLine("Date of birth is " + dateOfBirth.ToString("o"));

Answer 2

If you use DateTimeOffset it should fix your issue. Rather than trying to rewrite information that already exists I would point you to a couple of existing resources:

These uses for DateTimeOffset values are much more common than those for DateTime values. As a result, DateTimeOffset should be considered the default date and time type for application development.

From MSDN Development Guide

DateTime vs DateTimeOffset

Answer 3

I have tried using JsonConvert.DeserializeObject(jsonString) and got the expected output. Please check this fiddle

https://dotnetfiddle.net/uuZvab

Person person = JsonConvert.DeserializeObject<Person>(jsonString);
                DateTime dateOfBirth = DateTime.Parse(person.Data.DateOfBirth);
                if (dateOfBirth.Kind != DateTimeKind.Utc)
                {
                    dateOfBirth = dateOfBirth.ToUniversalTime();
                }
                Console.WriteLine("Date of birth is " + dateOfBirth.ToString("o"));