[英]mysql : updating existing column using the column value in prepared query
Old query was like this 旧查询是这样的
update tbl_order set `pack_id` =0, `pack_down_count`=pack_down_count + '".intval($_POST['item_number'])."',`price`='".$_POST['mc_gross']."', `otime`=Now(), `ptime`=Now(), status='paid', pack_download=pack_download + '".intval($_POST['item_number'])."' where member_id='".$_MYVAR['userid']."'"
I liked to change it to prepared statment , I am using a class from https://github.com/joshcam/PHP-MySQLi-Database-Class 我喜欢将其更改为准备好的语句,我使用的是https://github.com/joshcam/PHP-MySQLi-Database-Class中的类
for updating 用于更新
I changed the above query to 我将上面的查询更改为
$data = array(
'pack_id' =>$_MYVAR['pack_id'],
'pack_apply_count' =>`pack_apply_count` + intval($_POST['item_number']),
'price' =>$_POST['mc_gross'],
'otime' =>date('Y-m-d H:i:s'),
'ptime' =>date('Y-m-d H:i:s'),
'status' =>'paid',
'pack_apply' =>`pack_apply` + intval($_POST['item_number'])
);
$db->where('member_id',$_MYVAR['userid']);
$db->update("tbl_order",$data);
also tried without backticks around pack_apply_count and pack_apply but didn't update my table 还尝试了在pack_apply_count和pack_apply周围没有反引号的情况,但是没有更新我的表
$data = array(
'pack_id' =>$_MYVAR['pack_id'],
'pack_apply_count' =>pack_apply_count + intval($_POST['item_number']),
'price' =>$_POST['mc_gross'],
'otime' =>date('Y-m-d H:i:s'),
'ptime' =>date('Y-m-d H:i:s'),
'status' =>'paid',
'pack_apply' =>pack_apply + intval($_POST['item_number'])
);
$db->where('member_id',$_MYVAR['userid']);
$db->update("tbl_order",$data);
Please tell correct way to update the table 请告诉正确的方式更新表格
The link you provided will give you the information you need, look at the section Update Query . 您提供的链接将为您提供所需的信息,请参阅更新查询部分。
It seems you can increment with $db->inc($_POST['item_number'])
看来您可以使用$db->inc($_POST['item_number'])
As shown in the example: 如示例所示:
$data = Array (
'firstName' => 'Bobby',
'lastName' => 'Tables',
'editCount' => $db->inc(2),
// editCount = editCount + 2;
'active' => $db->not()
// active = !active;
);
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