[Rx.js] Zip运算符何时发出错误？

Question

I am learning Rx.js and have one problem with zip operator:

    var error =Rx.Observable.throw('Oop!');
    var age$ = Rx.Observable.concat(Rx.Observable.of(21,22,23),error);
    var sex$ = Rx.Observable.of("male","male","female","female");
    var name$ = Rx.Observable.of("jack","john","james","lucy");
    var example = Rx.Observable.zip(age$,sex$,name$,(age,sex,name)=>{ return {age,sex,name} });

and i subscribe the example source and print some message:

    example.subscribe({
        next: (value) => { console.log(value); },
        error: (err) => { console.log('Error: ' + err); },
        complete: () => { console.log('complete'); }
    });

the out put is not what i expected:

{age:21,sex:"male",name:"jack"}
{age:22,sex:"male",name:"john"}
{age:23,sex:"female",name:"james"}
error

but just one line with no value output :

    error

read the offical doc but no chapter explained when the zip operator emit error .

Can anyone help?thx very much.

Answer 1

You see the error straight away because the first observable that you pass emits its values synchronously. (The other observables emit their values synchronously, too, but that does not matter in this scenario.)

zip subscribes to the passed observables one by one and in the order in which they are passed. Upon subscribing to the first observable, zip synchronously receives all of the observable's values and the concatenated error. It then emits its own error and is done.

If you specify the optional scheduler argument - so that the observables emit their values asynchronously - you will see the behaviour you were expecting:

 var age$ = Rx.Observable.concat( Rx.Observable.of(21, 22, 23, Rx.Scheduler.async), Rx.Observable.throw("Oop!", Rx.Scheduler.async) ); var sex$ = Rx.Observable.of( "male", "male", "female", "female", Rx.Scheduler.async ); var name$ = Rx.Observable.of( "jack", "john", "james", "lucy", Rx.Scheduler.async ); var zipped$ = Rx.Observable.zip( age$, sex$, name$, (age, sex, name) => ({ age, sex, name }) ); zipped$.subscribe( (value) => console.log(value), (error) => console.log(error), () => console.log("complete") ); 

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