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使用Javascript xhr将对象作为参数发送

[英]Sending object as param with Javascript xhr

I have an array that has a structure similar to the following: 我有一个数组,其结构类似于以下内容:

var data = [
    {
        'name': 'Foo'
    },
    {
        'name': 'Bar'
    }
]

And I want to pass it to my php script with pure Javascript without relying on jQuery. 而且我想使用纯Javascript将其传递给我的php脚本,而不依赖jQuery。

So my jQuery version would be: 所以我的jQuery版本是:

$.ajax({
    'url': '/script.php',
    'method': 'POST',
    'data': {'inscriptions': data},
    'dataType': 'json',
    'success': function(response){
        // my code for handling the response
    }
});

And in Javascript I have the following: 在Javascript中,我有以下内容:

var xhr = new XMLHttpRequest();
xhr.open('POST', '/script.php', true);
xhr.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded; charset=UTF-8');
xhr.send(data);
xhr.onreadystatechange = function(event){

    if(event.target.readyState != XMLHttpRequest.DONE)
        return;

    // my code for handling the response

};

However the issue I'm having is that sending it this way in Javascript, my $_POST on the server side is empty because the 但是我遇到的问题是在Java中以这种方式发送它,我在服务器端的$_POST为空,因为

array(0){}

And if I change it to: 如果我将其更改为:

xhr.send(JSON.stringify({'inscriptions': data}));

Then on my server side my $_POST will be: 然后在我的服务器端,我的$_POST将是:

array (size=1)
    '{"inscriptions":' => 
        array (size=1)
            '{"name":"Foo"},{"name":"Bar"}' => string '' (length=0)

When I send it via jQuery I get the following: 当我通过jQuery发送它时,我得到以下信息:

array (size=1)
  'inscriptions' =>
    array (size=2)
      0 =>
        array (size=1)
          'name' => string 'Foo' (length=3)
      1 =>
        array (size=1)
          'name' => string 'Bar' (length=3)

Is there a way to achieve the same thing with pure Javascript? 有没有办法用纯Javascript实现相同的目的?

My questions has been marked as a duplicate of Send JSON data from Javascript to PHP? 我的问题被标记为将JSON数据从Javascript发送到PHP? but the answer doesn't answer my question. 但是答案没有回答我的问题。 They are using a way to 'bypass' it with: 他们正在使用一种“绕过”它的方式:

php://input

However, it's not sending it directly to the $_POST like jQuery does. 但是,它没有像jQuery那样直接将其发送到$_POST

xhr.setRequestHeader("Content-type", "application/json")
xhr.send(JSON.stringify({'inscriptions': data}));

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