使用列表中的名称创建类的实例

Question

There is a list of lists

[[name1, value1], [name2, value2], ...]

I need to create instances of a class with names name1, name2, and so forth, ie, with names taken from the list[1][1] , list[2][1] , etc. But I can't imagine ways in which this can be implemented.

Class:

class func():
    def __init__(self, visibility, ftype, body):
    ...

List:

list = [
    ['private', 'Void', 'SetupWheels', 'body'],
    ...
]

Dictionary:

func_list = {}

It should look like this:

for i, val in enumerate(c):
    *new key in the dictionary is equal to the value val[2]* = func(val[0], val[1], val[3])

Answer 1

To populate a dictionary with instances of a class whose attributes were taken from a list of lists, you can use a dict comprehension like:

Code:

func_list = {row[2]: Func(row[0], row[1], row[3]) for row in c}

Test Code:

class Func():
    def __init__(self, visibility, ftype, body):
        self.visibility = visibility
        self.ftype = ftype
        self.body = body

    def __repr__(self):
        return "v:%s f:%s b:%s" % (self.visibility, self.ftype, self.body)

c = [
    ['private', 'Void', 'SetupWheels', 'body'],
    ['private', 'Void', 'SetupWheelx', 'bo8y'],
]

func_list = {row[2]: Func(row[0], row[1], row[3]) for row in c}

print(func_list)

Results:

{'SetupWheelx': v: private f:Void b:body, 'SetupWheels': v: private f:Void b:body}