[英]SQL statement group? or sum?
im new to SQL so looking for some assistance. 我是SQL的新手,所以需要一些帮助。 heres my code
这是我的代码
Select
MITARBEITER_NR "ID",
DAUER "Duration",
datum "Date"
From
Vtsbreak
Where DATUM >= TO_DATE('2017/04/01', 'yyyy/mm/dd') AND DATUM <= TO_DATE('2017/05/27','yyyy/mm/dd')
order by datum
this is my data 这是我的数据
ID Duration Date
443 60 03/04/2017
412 10 03/04/2017
399 100 04/04/2017
374 10 04/04/2017
374 10 04/04/2017
376 120 04/04/2017
456 300 04/04/2017
372 120 04/04/2017
443 60 04/04/2017
446 300 04/04/2017
427 60 04/04/2017
403 420 04/04/2017
what I am trying to do is return the ID code, Date, sum of duration for that date I have tried using group but just returns one case of id 374 for 04/04/2017 with a value of 10 instead of 20 我想做的是返回ID码,日期,我尝试使用组的该日期的持续时间总和,但只返回ID 374 for 04/04/2017的一种情况,其值为10而不是20
any suggestions please? 有什么建议吗?
You want a GROUP BY
. 您想要
GROUP BY
。 Following the syntax you are using (but definitely not MySQL), you can do something like this: 按照您使用的语法(但绝对不是MySQL),您可以执行以下操作:
select MITARBEITER_NR as id,
to_char(datum, 'YYYY-MM-DD') as yyyymmdd,
sum(dauer) as duration
from Vtsbreak
where datum >= DATE '2017-04-01' and
datum < DATE '2017-05-28'
group by id, to_char(datum, 'YYYY-MM-DD')
order by yyyymmdd;
sorted it 排序
Select
MITARBEITER_NR "ID",
sum(DAUER) "Duration",
datum "Date"
From
Vtsbreak
Where DATUM >= TO_DATE('2017/04/01', 'yyyy/mm/dd') AND DATUM <= TO_DATE('2017/05/27','yyyy/mm/dd')
group by MITARBEITER_NR, datum;
order by datum
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.