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SQL-左联接中的表别名

[英]SQL - Table alias in Left Join

I am trying to write a simple SQL query with Left Join. 我试图用Left Join编写一个简单的SQL查询。

This is the query: 这是查询:

SELECT * 
FROM ( 
   SELECT * 
   FROM TRN_IN.COIT AS TRANSMISSIONS
     LEFT JOIN ( 
       SELECT TRNNumber ,COUNT(ID) 
       FROM TRN_IN.COIT AS TOTAL_LINES   
       WHERE DataPiece02 = 'TO'   
       GROUP BY TRNNumber 
   ) ON TRANSMISSIONS.TRNNumber  = TOTAL_LINES.TRNNumber
)

Second table alias is TOTAL_LINES. 第二个表别名为TOTAL_LINES。

When running it, I get an error that TOTAL_LINES is not listed. 运行它时,出现错误,未列出TOTAL_LINES。

The strange thing is, that When trying to run the second query by itself, there is no error: 奇怪的是,当尝试自行运行第二个查询时,没有错误:

(SELECT TRNNumber ,COUNT(ID) 
 FROM TRN_IN.COIT AS TOTAL_LINES 
 WHERE DataPiece02 = 'TO' 
 GROUP BY TRNNumber )

Anybody has a clue? 有人知道吗?

Hope you are assign the AS TOTAL_LINES table alias name in the wrong place. 希望您在错误的位置分配了AS TOTAL_LINES表别名。

Placing the table alias name after second sub query will solve your problem. 在第二个子查询之后放置表别名名称将解决您的问题。

Can you try the query below: 您可以尝试以下查询:

SELECT *
FROM (
    SELECT *
    FROM TRN_IN.COIT AS TRANSMISSIONS
    LEFT JOIN (
        SELECT TRNNumber
            ,COUNT(ID) AS CountDetails
        FROM TRN_IN.COIT 
        WHERE DataPiece02 = 'TO'
        GROUP BY TRNNumber
        ) AS TOTAL_LINES ON TRANSMISSIONS.TRNNumber = TOTAL_LINES.TRNNumber
    ) AS Result

TOTAL_LINES must be the alias of the whole select, not on the table in from clause. TOTAL_LINES必须是整个select的别名,而不是from子句中的表。 Change To: 改成:

SELECT * FROM ( SELECT * FROM TRN_IN.COIT AS TRANSMISSIONS

LEFT JOIN ( SELECT TRNNumber ,COUNT(ID) FROM TRN_IN.COIT WHERE DataPiece02 = 'TO'   GROUP BY TRNNumber ) AS TOTAL_LINES   

ON TRANSMISSIONS.TRNNumber  = TOTAL_LINES   .TRNNumber)

Try this.. 尝试这个..

SELECT TOTAL_LINES.TRNNumber,COUNT(TOTAL_LINES.ID) FROM TRN_IN.COIT TRANSMISSIONS LEFT JOIN TRN_IN.COIT TOTAL_LINES 
ON TRANSMISSIONS.TRNNumber  = TOTAL_LINES.TRNNumber
WHERE TOTAL_LINES.DataPiece02 = 'TO'   GROUP BY TOTAL_LINES.TRNNumber;

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