[英]Missing variable data from SQL
I have called the data from SQL and selected by id then i would like to use the data from "mysqli_fetch_array" row[1] to do some calculation. 我从SQL调用了数据,并按ID选择了数据,然后我想使用“ mysqli_fetch_array”第[1]行中的数据进行一些计算。
but somehow at line 14 the $row[1] can't get the date to do calculation. 但是以某种方式在第14行,$ row [1]无法获得进行计算的日期。
index.php 的index.php
<?php
$con = mysqli_connect('localhost','root','','test2');
$query = mysqli_query($con,"SELECT * FROM count") or
die(mysqli_error($con));
while( $row = mysqli_fetch_array($query))
echo "$row[id]. $row[quantity] <a href='edit.php?edit=$row[id]'>Draw
Patrs<br />";
?>
edit.php edit.php
<?php
if( isset($_GET['edit']) )
{
$id = $_GET['edit'];
$con = mysqli_connect('localhost','root','','test2');
$query = mysqli_query($con,"SELECT * FROM count WHERE id='$id'");
$row = mysqli_fetch_array($query);
}
if( isset($_POST['drawquantity']) )
{
$drawquantity = $_POST['drawquantity'];
$newquantity = $row[1]-$drawquantity;
$id = $_POST['id'];
$sql = "UPDATE count SET quantity='$newquantity' WHERE id='$id'";
$con = mysqli_connect('localhost','root','','test2');
$res = mysqli_query($con,$sql)
or die("Could not update".mysql_error());
echo "<meta http-equiv='refresh' content='0;url=index.php'>";
}
?>
<form action="edit.php" method="POST">
How mant you will take away: <input type="text" name="drawquantity" value=""
placeholder="<?php echo $row[1]; ?>"><br />
<input type="hidden" name="id" value="<?php echo $row[0]; ?>">
<input type="submit" value=" Update "/>
</form>
<?php
if( isset($_GET['edit']) )
{
$id = $_GET['edit'];
$con = mysqli_connect('localhost','root','','test2');
$query = mysqli_query($con,"SELECT * FROM count WHERE id='$id'");
$row = mysqli_fetch_array($query);
}
if( isset($_POST['drawquantity']) )
{
$drawquantity = $_POST['drawquantity'];
$newquantity = $row[1]-$drawquantity;
$id = $_POST['id'];
$sql = "UPDATE count SET quantity='$newquantity' WHERE id='$id'";
$con = mysqli_connect('localhost','root','','test2');
$res = mysqli_query($con,$sql)
or die("Could not update".mysql_error());
echo "<meta http-equiv='refresh' content='0;url=index.php'>";
}
?>
<form action="edit.php?edit=<?=$_GET['edit']?>" method="POST">
How mant you will take away: <input type="text" name="drawquantity" value=""
placeholder="<?php echo $row[1]; ?>"><br />
<input type="hidden" name="id" value="<?php echo $row[0]; ?>">
<input type="submit" value=" Update "/>
</form>
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