读取文件-逐行在c中创建排列

Question

So I'm having issues attempting to read a text file consisting of three lines. I am trying to read each line and create permutations per line. I want to continue looping through doing this to every line until I hit EOF. I'm trying to implement fgets within the while loop in my main. Am I on the right track? The main issue I am having is passing a char to my permutation method in my main.

#include <stdio.h>

void swap(char *x, char *y)
{
    char tempVariable;

    tempVariable = *x;
    *x = *y;
    *y = tempVariable;
}

void stringPermutation(char *a, int zeroVariable, int factorial)
{
    int i;

    if(zeroVariable == factorial)
    {
        printf("%s\n", a);
    }
    else
    {
        for(i = zeroVariable; i <= factorial; i++)
        {
            swap((a + zeroVariable), (a + i));
            stringPermutation(a, zeroVariable + 1, factorial);
            swap((a + zeroVariable), (a + i));
            }
        }
    }

int main(int argc, char *argv[])
    {
    if(argc != 2)
    {       
        printf("ERROR - WRONG AMOUNT OF ARGUMENTS\n");

    }
     else
    {   
        FILE *file = fopen(argv[1], "r");
        int x;

        printf("PERMUTATIONS:\n");

        while((x = fgetc(file)) != EOF)
        {   
            stringPermutation(x, 0, x - 1); //I'm messing up here
        }
        fclose(file);
    }
    return 0;
}

Answer 1

stringPermutation(x, 0, x - 1);

x is of type int , gets ASCII code of char as value but the function stringPermutation expects char *a

I suggest using fgets for reading lines of a file.

Answer 2

stringPermutation() is expecting a char* not a char or an int . You are passing a char . It looks like stringPermutation is using the parameter as a char* too and so in this case the caller is wrong.

Looks like you need to read a few chars into a buffer and pass the buffer to stringPermutation() . More simply use fgets or getline etc to read a string in one call instead of building it char by char yourself.