bash shell使用break将文件从一个位置复制到另一个位置并继续

Question

I have small script to copy the all the files from one directory (SRC) to another directory (DES). This below script is running perfectly.

#!/bin/bash

SRC="/home/user/dir1/*"
DES="/home/user/dir2/"

for file in "$SRC"
do
       if [ -f "$file" ]
       then
              cp "$file" "$DES"
              echo "$file -----> file copied"   
       fi
done

Now what i am thinking while copying files from one directory to another directory, how to skip the copying file if that file has already exist in (DES) directory with same name of (SRC) directory and continue the remaining file as usual from source to destination?

Here how to i use break and continue looping to perform this action?

Thanks,

Answer 1

I recommend to use rsync :

src="/home/user/dir1/"
dst="/home/user/dir2/"
rsync -rav --ignore-existing "${src}" "${dst}"

The switch --ignore-existing tells rsync to skip files which exist at the destination.

Answer 2

Why not just reduce the entire script to a oneliner?

cp -n /home/user/dir1/* /home/user/dir2/

The -n flag ( --no-clobber ) prevents cp from overwriting existing files.

If your real situation is more complicated, you can also take a look at rsync .