[英]Limit LISTAGG results in Oracle
I'm trying to limit one of my columns in my SQL query that uses LISTAGG to only group the first 3 rows into a single column. 我试图在使用LISTAGG的SQL查询中限制我的一列,以仅将前3行分组为一个列。
For instance: 例如:
Table
-----
Name Orders
---------------
Joe Joe_Order1
Joe Joe_Order2
Joe Joe_Order3
Joe Joe_Order4
Joe Joe_Order5
Joe Joe_Order6
Mark Mark_Order1
Mark Mark_Order2
Mark Mark_Order3
Mark Mark_Order4
Have it return the following... 让它返回以下内容...
Name Recent_Orders
-----------------------------
Joe Joe_Order1, Joe_Order2, Joe_Order3
Mark Mark_Order1, Mark_Order2, Mark_Order3
I'm able to concatenate the data using listagg however, I'm not entirely sure how to limit the results to the first 3 records. 我可以使用listagg连接数据,但是我不确定如何将结果限制为前3个记录。
SELECT NAME, LISTAGG(Orders, ', ') within group(order by Orders)
as Recent_Orders
FROM
Order_table
GROUP BY
NAME
Is this possible with LISTAGG? LISTAGG有可能吗? Any help would be greatly appreciated. 任何帮助将不胜感激。 Thanks 谢谢
Apply a row_number in a CTE, then apply the restriction in the WHERE clause 在CTE中应用row_number,然后在WHERE子句中应用限制
with CTE as
(
select row_number() over(partition by NAME order by Orders) as rn,
a1.*
from Order_Table a1
)
SELECT NAME, LISTAGG(Orders, ', ') within group(order by Orders)
as Recent_Orders
FROM
CTE
WHERE
rn <=3
GROUP BY
NAME
You can do this by enumerating the rows and using case
: 您可以通过列举行并使用case
来做到这一点:
SELECT NAME,
LISTAGG(CASE WHEN seqnum <= 3 THEN Orders END, ', ') WITHIN GROUP (ORDER BY Orders) as Recent_Orders
FROM (SELECT o.*, ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY ?? DESC) as seqnum
FROM Order_table o
) o
GROUP BY NAME;
By default, LISTAGG()
ignores NULL
values, so this does what you want. 默认情况下, LISTAGG()
忽略NULL
值,因此您可以执行所需的操作。
The ??
??
is the column for specifying the ordering. 是用于指定顺序的列。 SQL tables represent unordered sets; SQL表表示无序集; there is no "first three" or "last three" unless a column specifies the ordering. 除非有列指定顺序,否则没有“前三个”或“后三个”。
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