SQL / SQlite嵌套select in having子句

Question

I was playing a bit with sqlite and encountered the following problem: it looks like it is not possible to nest a subquery in a having clause

When I try to call a query with:

... having count(select * from produkt) > 1

I get the error:

OperationalError: near "select": syntax error

While executing

 ... having count(1) > 1 

everything is fine

Would you have any workarounds for that?

edit2:

I want to write this:

select distinct standort.name, standort.ort
from produktion
    join standort on id_standort = standort.id
    join produkt on id_produkt = produkt.id
where produkt.gewicht < 1

EXCEPT

select distinct standort.name, standort.ort
from produktion
    join standort on id_standort = standort.id
    join produkt on id_produkt = produkt.id
where produkt.kategorie = "Spiel"

In a more elegant way, using "having"

Cheers and thanks a lot!

Wojtek

Answer 1

I think this fits your intention better than your current select

SELECT ... 
FROM Standort
     JOIN produktion ...
     JOIN produkt ...
WHERE product.kategorie != "Spiel" AND produkt.gewicht > 1

Answer 2

I'm not sure in what context you would do this, but this is syntactically correct:

having (select count(*) from produkt) > 1

EDIT:

For your actual question, this query is simpler:

select s.name, s.ort
from produktion pn join
     standort s
     on pn.id_standort = s.id join
     produkt p
     on pn.id_produkt = p.id
group by s.name, s.ort
having sum(case when p.gewicht < 1 then 1 else 0 end) > 0 and
       sum(case when p.kategorie = 'Spiel' then 1 else 0 end) = 0;

This returns all s.name / s.ort combinations that have a "gewicht" less than 1 and no "kategorie" called 'Spiel' .