如何使用一个查询的结果，比如另一个查询的参数？？ 甲骨文

Question

I have a query that returns this

SELECT COLNAME FROM TABLE_1 WHERE CATALOG_ID = 40;

    COLNAME
    ----------------
    CONVERTED_VALUE
    CONVERTED_VALUE_01
    CONVERTED_VALUE_02
    CONVERTED_VALUE_03
    VALUE_DESCRIPTION

I need to convert this result into a query like the next:

SELECT CONVERTED_VALUE, CONVERTED_VALUE_01, CONVERTED_VALUE_02, 
CONVERTED_VALUE_03 , VALUE_DESCRIPTION 
FROM TABLE2 WHERE CATALOG_ID = 40;

Is posible to do this in a single query I don't know for example

SELECT( SELECT COLNAME FROM TABLE_1 WHERE CATALOG_ID = 40 ) 
FROM TABLE_2 WHERE CATALOG_ID = 40;

Obviously that doesn't work but is the idea :)

I really don't know how to achieve this. Any suggestion guys? I'm not an expert at using databases :(

I'm using Oracle 10.

The idea is basically convert the result of the first query into the parameters of the second one.

Answer 1

I think this is what you're looking for, as long as my understanding of your question is correct:

SELECT
  t.CONVERTED_VALUE,
  t.CONVERTED_VALUE_01,
  t.CONVERTED_VALUE_02, 
  t.CONVERTED_VALUE_03,
  t.VALUE_DESCRIPTION
FROM
  (SELECT COLNAME FROM TABLE_1 WHERE CATALOG_ID = 40) t,
  TABLE_2
WHERE TABLE_2.CATALOG_ID = 40;

If i'm not understanding what you're asking let me know.

Answer 2

This is what came to my mind. But firing select statement from anonymous block would not look nice.

DECLARE
    V_COL VARCHAR2(100):='';
    s_ql VARCHAR2(200):='';
BEGIN
    SELECT LISTAGG(COLNAME,',') WITHIN GROUP(ORDER BY COLNAME) AS COL INTO V_COL FROM TABLE_1 WHERE CATALOG_ID = 40 group by CATALOG_ID;
    s_ql:='SELECT '||V_COL||' FROM TABLE2 WHERE CATALOG_ID = 40';
    EXECUTE IMMEDIATE (s_ql);
END

You can use some variable or collection to capture result and display it using DBMS_OUTPUT .

Answer 3

select语句的返回格式与我们需要提供的列名格式不匹配，所以我猜这是不可能的:(