Fancytree JQuery-获取节点子级和子级子级

Question

I'm using Fancytree ( https://github.com/mar10/fancytree ) and I have this tree structure:

root
 |_ child1
      |_ subchild1
      |_ subchild2
            |_ subchild3
            |_ subchild4

If the the selected node is child1 I can get the first children using window.tree.activeNode.children or window.tree.activeNode.getChildren() but that only return [subchild1, subchild2] . There are anyway get all the children?

A method that return: [subchild1, subchild2, subchild3, subchild4] ?

Answer 1

You could use the visit function to generate a flat list:

var activeNode = tree.getActiveNode(),
    nodes = [];

activeNode.visit(function(node) {
    nodes.push(node);  // or node.key, ...
});

(Note that there is also the node.toDict() method to generate a nested object instead.)