[英]How can I print a non UTC timestamp using datatable (DT package) in Rmarkdown?
I have some timestamps stored in different time-zones that I would like to include in a datatable using DT
package within a rmarkdown
document. 我有一些时间戳存储在不同的时区,我想在rmarkdown
文档中使用DT
包包含在数据rmarkdown
。
I would like to display the timestamp in the stored time-zone but for some reason datatable
converts it to UTC. 我想,以显示存储的时区,但由于某些原因,时间戳datatable
将其转换为UTC。 The behaviour when I use print
is what I want but the format is not nice. 我使用print
时的行为是我想要的但是格式不好。
How can I achieve the same behaviour with datatable
and print
? 如何使用datatable
和print
实现相同的行为?
Here a minimal working example of the rmarkdown
file: 这是rmarkdown
文件的最小工作示例:
---
title: "MinorQ"
output: html_document
---
```{r setup}
library(DT)
df=data.frame(timestamp=as.POSIXct("2017-01-01 12:34:56",tz="CET"))
df$tzone=attr(df$timestamp,"tzone")
datatable(df)
print(df)
```
As mentioned in my comment you could just convert your POSIXct elements to character: 正如我在评论中提到的,你可以将你的POSIXct元素转换为字符:
input <- format(as.POSIXct("2017-01-01 12:34:56", tz = "CET"), format = '%F %T %Z')
str(input)
# chr "2017-01-01 12:34:56 CET"
This does not mean that you cannot use different timezones. 这并不意味着您不能使用不同的时区。 When reading from the table you could use gsub
to get your dates with the correct timezone: 从表中读取时,您可以使用gsub
以正确的时区获取日期:
# First gsub: remove all capital letters (so only date and time remain)
# Sec. gsub: remove all characters exept capital letters (so only CET, UTC, etc. remain).
out <- as.POSIXct(gsub(input, pattern = "[A-Z]", replacement = ""),
format = '%F %T',
tz = gsub(input, pattern = "[^A-Z]", replacement = ""))
str(out)
# POSIXct[1:1], format: "2017-01-01 12:34:56"
lubridate::tz(out)
# [1] "CET"
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