在Javafx中检查TreeItem的条件后，如何在treeView中选择treeItem

Question

I have downloaded familyTree project and it doesn't have the ability to search for an specific family member!

I have added a search button to it, and in the handler method section, I need the code that searches for a member that has the specified socialID , and select it (scroll it to the sight, and make it blue (selected)). But I don't know how to programmatically select a treeItem, and make it visible and selected?

My code:

 @FXML
private void btnSearch_click(ActionEvent event){


    for(TreeItem<FamilyMember> treeItem:root.getChildren()){

              if(treeItem.getValue().getNationality().toString()=="22"){
                 // treeView.setSelectionModel(item);
                 treeView.getSelectionModel().select(treeItem);
                  //it still doesnt select the item with nationality=="22"
                break;
              }

    }
}

Answer 1

You can select the item with

treeView.getSelectionModel().select(item);

and if you still need to scroll (I think selecting it might automatically scroll to it), do

treeView.scrollTo(treeView.getRow(item));

A couple of notes:

1. I do not understand the for loop. Why are you doing

    TreeItem<FamilyMember> item = root.getChildren().get(i); 

   and why are you creating the index i ? What is wrong with the treeItem variable you already defined in the loop syntax? Isn't this necessarily exactly the same thing as item ?

2. You need to read How do I compare strings in Java?