将正则表达式与无序的字母和数字字符串匹配

Question

I have product names for which I have to find the model numbers. For example

KIPOR KDE38SS3 DIESEL 400V AGGREGAATTI # Result --> KDE38SS3 
KIPOR KDE28SS3 DIESEL 400V AGGREGAATTI # Result --> KDE28SS3 
KIPOR KDE19STA3  19 KW GENERAATTORI 400V # Result --> KDE19STA3  
KRÄNZLE C895-1 KUUMAVESIPESURI KELALLA # Result --> C895-1
KRÄNZLE 1165-1 KUUMAVESIPESURI KELALLA # Result --> 1165-1
NILFISK MH 4M-200/960 FA KUUMAVESIPESURI # Result --> MH 4M-200/960 FA
WALLIUS LMP-452i MIG HITSAUSKONE # Result --> LMP-452i
KRÄNZLE C15/150 KUUMAVESIPESURI KELALLA # Result --> C15/150

My current code is simple and work in some cases but I want to get an efficient way.

for i in range (10):
    modelnum = re.findall(r'\w+\d+\w+', productnames[i])
    print(modelnum)

Results:

['KDE38SS3', '400V']
['KDE28SS3', '400V']
['KDE19STA3Â', '400V']
['C895']
['1165']
['200', '960']
['452i']
['C15', '150']

Is there a way I can only parse model no. because in the results I am also getting 400V which is not a model no. and also one model no. is broken in two elements.

Answer 1

If you don't mind using a capturing group, and the model number is always the first match in the line, then you could do something like this:

for i in range (10):
    modelnum = re.findall(r'^.*?(\w+\d+\w+)', productnames[i])
    print(modelnum)