[英]How to convert a list of numbers into a string?
What I'm trying to do is take a given list: 我要做的是拿一个给定的列表:
numlist_1: [3, 5, 4, 2, 5, 5]
and convert it to a string using this function 并使用此函数将其转换为字符串
def to_string(my_list, sep=', '):
newstring = ''
count = 0
for string in my_list:
if (length(my_list)-1) == count:
newstring += string
else:
newstring += string + sep
count += 1
return newstring
With the desired output to appear as: 所需的输出显示为:
to_string Test List is: 3, 5, 4, 2, 5, 5 List is: 3 - 5 - 4 - 2 - 5 - 5
However, I get an error which says 但是,我收到一个错误
TypeError: unsupported operand type(s) for +: 'int' and 'str' TypeError:+:'int'和'str'的不支持的操作数类型
I think this is because one of the print statements is 我认为这是因为其中一个印刷声明是
print('List is:', list_function.to_string(num_list1, sep=' - '))
and the separator is different from the one given in the function but I want to be able to accompany for both ', ' and ' - ' seperators as I have another list which uses the same function with the ', ' seperator instead. 并且分隔符与函数中给出的分隔符不同,但我希望能够同时包含','和' - '分隔符,因为我有另一个列表,它使用与','分隔符相同的函数。
How do I get around this? 我该如何解决这个问题?
You can try this 你可以试试这个
def to_string(my_list, sep=', '):
newstring = ''
count = 0
for string in my_list:
if (length(my_list)-1) == count:
newstring += str(string)
else:
newstring += str(string) + sep
count += 1
return newstring
However, a much concise way is this: 但是,这是一个非常简洁的方法:
sep = ', '
sep.join(map(str,my_list))
Another option: 另外一个选项:
sep = ', '
output_str = sep.join([str(item) for item in my_list])
another way to solve this problem 另一种解决这个问题的方法
L = [1,2,3,4,-5]
sep = ""
print(sep.join(list(map(str,L))))
hope this helps 希望这可以帮助
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