[英]urllib.Request remove Content-Type header
I want to remove the content-type header from a POST request.我想从 POST 请求中删除内容类型标头。 I have tried setting the header to
''
我试过将标题设置为
''
try:
from urllib.request import Request, urlopen
except ImportError:
from urllib2 import Request, urlopen
url = 'https://httpbin.org/post'
test_data = 'test'
req = Request(url, test_data.encode(), headers={'Content-Type': ''})
req.get_method = lambda: 'POST'
print(urlopen(req).read().decode())
But this sends:但这会发送:
{
// ...
"headers": {
"Content-Type": "", // ...
}
// ...
}
What I would like it to do is send no Content-Type at all, instead of a blank one.我希望它做的是根本不发送 Content-Type,而不是发送一个空白的。 By default, it is
application/x-www-form-urlencoded
.默认情况下,它是
application/x-www-form-urlencoded
。
This can easily be acheived with requests
:这可以通过
requests
轻松实现:
print(requests.post(url, test_data).text)
But this is a script I need to distribute, so cannot have dependencies.但这是我需要分发的脚本,因此不能有依赖项。 I need it to have no Content-Type at all, since the server is very picky, so I cannot use
text/plain
or application/octet-stream
.我需要它根本没有 Content-Type ,因为服务器非常挑剔,所以我不能使用
text/plain
或application/octet-stream
。
You can specify custom handler:您可以指定自定义处理程序:
try:
from urllib.request import Request, urlopen, build_opener, BaseHandler
except ImportError:
from urllib2 import Request, urlopen, build_opener, BaseHandler
url = 'https://httpbin.org/post'
test_data = 'test'
class ContentTypeRemover(BaseHandler):
def http_request(self, req):
if req.has_header('Content-type'):
req.remove_header('Content-type')
return req
https_request = http_request
opener = build_opener(ContentTypeRemover())
req = Request(url, test_data.encode())
print(opener.open(req).read().decode())
Another (hacky) way: monkey-patching the request object to pretend there's Content-type
header already there;另一种(hacky)方式:猴子修补请求对象以假装已经存在
Content-type
标头; prevents AbstractHTTPHandler
to default Content-Type header.防止
AbstractHTTPHandler
使用默认的 Content-Type 标头。
req = Request(url, test_data.encode())
req.has_header = lambda header_name: (header_name == 'Content-type' or
Request.has_header(req, header_name))
print(urlopen(req).read().decode())
Just to add ontop of @falsetru's answer,只是为了添加@falsetru的答案,
If you need to filter more headers than this, req.headers
is not the thing you want, it's more like this:如果你需要过滤比这更多的标题,
req.headers
不是你想要的,它更像是这样的:
class ContentTypeRemover(BaseHandler):
def __init__(self, headers_to_filter={'Content-type'}): # set or dict works
self.headers_to_filter = headers_to_filter
def http_request(self, req):
for header, value in req.header_items():
if header in self.headers_to_filter:
req.remove_header(header)
return req
https_request = http_request
And if you need to modify a header, not remove it.. It gets a bit weird (at least this is the only method I've found to be working):如果你需要修改一个标题,而不是删除它......它变得有点奇怪(至少这是我发现唯一有效的方法):
req.remove_header(header)
req.add_header(header, self.modify_headers[header.lower()])
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