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在react.js中为组件设置cookie

[英]Set up cookie for the component in react.js

I have read this article How can I do to set cookie in the react code? 我已经阅读了这篇文章如何在React代码中设置cookie? about setting up cookie in reactjs code, however, I cannot use any library, what I can use is just the javascrip. 关于在reactjs代码中设置cookie,但是,我不能使用任何库,只能使用javascrip。 Now, what I want to achieve is to show up a welcome box for the first time visit. 现在,我想要实现的是在第一次访问时显示一个欢迎框。 What I have done and tested are: 1.the welcome box, it is a component coding in jsx; 我已经完成并测试的是:1.欢迎框,它是jsx中的组件编码; 2. the cookie coding in js. 2. js中的cookie编码。 Both sub-part are tested working, however, when I tried to combine these two part into a single component, it is not working. 这两个子部分都经过测试工作,但是,当我尝试将这两个部分组合为一个组件时,它就无法工作。

 var Child = React.createClass({ render: function() { return ( <div className="container"> <p>Welcome to our website</p> <button onClick={this.props.onClick}>Click me to close</button> </div> ); } }); var ShowHide = React.createClass({ createCookie(name,value,days) { if (days) { var date = new Date(); date.setTime(date.getTime()+(days*24*60*60*1000)); var expires = "; expires="+date.toGMTString(); } else var expires = ""; document.cookie = name+"="+value+expires+"; path=/"; }, readCookie(name) { var nameEQ = name + "="; var ca = document.cookie.split(';'); for(var i=0;i < ca.length;i++) { var c = ca[i]; while (c.charAt(0)==' ') c = c.substring(1,c.length); if (c.indexOf(nameEQ) == 0) return c.substring(nameEQ.length,c.length); } return ""; }, eraseCookie(name) { createCookie(name,"",-1); }, firstVisit() { var isFirstVisit; var result = readCookie('firstVisit'); if (result == "") { createCookie('firstVisit', 'true', 365); isFirstVisit = true; return isFirstVisit; } else { isFirstVisit = false; return isFirstVisit; } }, getInitialState: function () { if(firstVisit()) { return { childVisible: true }; } else { return { childVisible: true }; } }, onClick: function() { this.setState({childVisible: !this.state.childVisible}); }, render: function() { return( <div> { this.state.childVisible ? <Child onClick={this.onClick} /> : null } </div> ) }, }); React.render(<ShowHide />, document.getElementById('container')); 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> 

Alternatively to cookies you could use localStorage . localStorage cookie,您可以使用localStorage Here's a basic example of that. 这是一个基本的例子。 It sets an item in the storage once the main component is mounted and reacts to that item in the render() method. 一旦安装了主要组件,它将在存储中设置一个项目,并在render()方法中对该项目做出反应。

componentDidMount() {
  // Get item from localStorage and save it to a constant.
  const hasVisitedBefore = localStorage.getItem('hasVisitedBefore');

  // Check if the user has visited the site (component) before.
  if (!hasVisitedBefore) {
    // If not, set the component state (or dispatch an action if you need)
    // Also set the localStorage so it's globally accessible.
    this.setState({ hasVisitedBefore: false });
    localStorage.setItem('hasVisitedBefore', true);
  }
}

// Based on the state set in `componentDidMount()`, show or hide the welcome modal.
render() {
  return (
    <div>
      {this.state.hasVisitedBefore
        ? 'Welcome back!'
        : 'Welcome for the first time!'}
    </div>
  );
}

Working demo on JSFiddle . JSFiddle上的工作演示

In other components you could then just check for localStorage.getItem('hasVisitedBefore') and render things based on that. 然后,在其他组件中,您只需检查localStorage.getItem('hasVisitedBefore')并根据该内容进行渲染即可。

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