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无法转换为 java.lang.Comparable

[英]cannot cast to java.lang.Comparable

Although this question has already been asked but I have an implementation specific doubt.虽然已经问过这个问题,但我有一个具体的实施疑问。

I am trying to print the top view of the binary tree and following is the complete code for it:我正在尝试打印二叉树的顶视图,以下是它的完整代码:

import java.util.*;

class Node{
    int data;
    Node right;
    Node left;
    Node(int data){
        this.data = data;
    }
}

class Pair<F,S>{
    private F first;
    private S second;
    public Pair(F first, S second){
        this.first = first;
        this.second = second;
    }
    
    public F getFirst(){return first;}
    public S getSecond(){return second;}
}

class BinaryTreeTopView{

    public static void printTopView(Node root){

        if(root == null)
            return;

    Queue <Pair<Node,Integer>> q = new Queue<>();
    Map <Integer,Node> map = new HashMap<>();
    Pair<Node,Integer> p = new Pair<>(root, 0);
    q.add(p);
    
    /*
    I am storing nodes and the corresponding horizontal distances 
    in the form of a pair which then are being stored in the queue
    to ensure level order traversal
    */

    while(!q.isEmpty()){
        Pair<Node,Integer> temp = q.peek();
        q.remove();

        if(map.containsKey(temp.getSecond())==true){
            map.put(temp.getSecond(),temp.getFirst());
        } else {
            System.out.println(temp.getFirst().data);
            map.put(temp.getSecond(),temp.getFirst());                
        }

        if(temp.getFirst().left!=null){
            Pair<Node,Integer> left = new Pair<>(temp.getFirst().left, temp.getSecond()-1);
            q.add(left);
        }
        
        if(temp.getFirst().right!=null){
            Pair<Node,Integer> right = new Pair<> (temp.getFirst().right, temp.getSecond()+1);
            q.add(right);
        }
        
    }
}
public static void main(String[] args) {
    Node root = new Node(1);
    root.left = new Node(2);
    root.right = new Node(3);
    root.left.right = new Node(5);
    root.left.left = new Node(4);
    root.right.left = new Node(6);
    root.right.right = new Node(7);
    root.right.left.right = new Node(8);
    root.right.right.left = new Node(10);
    root.right.right.right = new Node(9);
    root.right.right.left.right = new Node(11);
    root.right.right.left.right.right = new Node(12);
    
    printTopView(root);
}
}

It compiles fine but an exception is being raised at the runtime.它编译得很好,但在运行时引发了异常。 Now I have been getting the following exception and I am unable to figure out what the problem is:现在我得到了以下异常,我无法弄清楚问题是什么:

Exception in thread "main" java.lang.ClassCastException: 
Pair cannot be cast to java.lang.Comparable at  java.util.PriorityQueue.siftUpComparable(PriorityQueue.java:652)
at java.util.PriorityQueue.siftUp(PriorityQueue.java:647)
at java.util.PriorityQueue.offer(PriorityQueue.java:344)
at java.util.PriorityQueue.add(PriorityQueue.java:321)

It's because Pair isn't implementing Comparable.这是因为 Pair 没有实现 Comparable。 Either implement it:要么实现它:

public class Pair implements Comparable<Pair> {
    public int compareTo(Pair o) {
        // ...
    }
}

Or use Comparator in Your priority queue或者在你的优先队列中使用 Comparator

Using Comparator ;使用比较器;

PriorityQueue<DummyObject> pq = new
             PriorityQueue<DummyObject>(5, new DummyObjectComparator());

Define your Comparator :定义你的比较器:

class DummyObjectComparator implements Comparator<DummyObject>{

      // Overriding compare()method of Comparator 

       public int compare(DummyObject s1, DummyObject s2) {
                   //some code
       }
 }

You're trying to add Pair instances to a PriorityQueue , so your Pair class must be Comparable .您正在尝试将Pair实例添加到PriorityQueue ,因此您的Pair类必须是Comparable A reasonable implementation could be to force F and S to be Comparable on their own right, and then compare by the first element, and then the second one:一个合理的实现可能是强制FS自己是可Comparable ,然后按第一个元素进行比较,然后是第二个:

class Pair<F extends Comparable<F>, S extends Comparable<S>>
    implements Comparable<Pair<F, S>> {

    // All the code you already have is fine

    @Override
    public int compareTo(Pair<F, S> o) {
        int retVal = getFirst().compareTo(o.getFirst());
        if (retVal != 0) {
            return retVal;
        }
        return getSecond().compareTo(o.getSecond());
    }
}

Your statement:你的声明:

Queue <Pair<Node,Integer>> q = new Queue<>();

Doesn't compile because Queue is an interface and cannot be instantiated.无法编译,因为Queue是一个接口并且无法实例化。 I suspect that you've used a PriorityQueue instead.我怀疑您使用的是PriorityQueue

Do you really need a priority queue, or would a simple LinkedList would suit your algoritm?你真的需要一个优先队列,还是一个简单的LinkedList适合你的算法?

UPDATE:更新:

BTW, with a LinkedList , the output is:顺便说一句,使用LinkedList ,输出为:

1 2 3 4 7 9 1 2 3 4 7 9

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