如何解决Python 2.7中以下代码的语法错误？

Question

I have used the following code for optimizing a problem via pyomo , coopr .

However the compiler gives an error, as follows:

invalid syntax

I tried to use correct syntax but I can not find the error:

model = AbstractModel()
model.x = Var(initialize = 1.5)
model.y = Var(initialize = 1.5)
import pyomo
from coopr.pyomo import *
def rosenbrock(model):
    return (1.0-model.x)**2 \
           + 100.0*(model.y - model.x**2)**2
model.obj=Objective(rule=rosenbrock, sense=minimize)
SyntaxError: invalid syntax

Answer 1

That code appears to be syntactically valid. Indeed I have just successfully compiled it in Python 3.6

Two possibilities occur to me:

1. There is a problem with your line continuation. Note that the backslash must be followed only by exactly the new line character. If you have additional white space then this will cause an error. For that reason, Python programmers are recommended to avoid line continuation.

2. The environment in which this code is running is a specialised embedded Python with some special constraints of which I am not aware.

Hope one of these helps ...