如何在Windows批处理文件中获取返回的值

Question

In Windows batch file I want the return value ie the apkVerison number. When I run gulp getVersion on the command line or inside a batch file it works fine. I want save the version number to a variable inside the batch file.

gulpfile.js:
  gulp.task('getVersion', function () {
      var data = require('./package.json')
      console.log('Version = ' + data.apkDependencies.apkVersion)
      return data.apkDependencies.apkVersion;
    });

abc.bat:
    set x=gulp getVersion 
    echo %x%

The batch file does not work. echo just echos "gulp getVersion"

Sorry I should have mentioned when I run gulp this is its output

gulp getVersion
[22:16:44] Using gulpfile ~\CareWheelsCorp\CareWheels\gulpfile.js
[22:16:44] Starting 'getVersion'...
Version = 9.1.13
[22:16:44] Finished 'getVersion' after 1.91 ms

As you can see Version is hidden inside, I need that 9.1.13 number

Answer 1

It works perfectly happily - just as you have asked it to do, to echo the contents of x .

If you want to execute the contents of x , you need

%x%

and if you want to get the return value, you need

for /f "delims=" %%r in ('%x%') do set "return=%%r"
echo %return%

(assuming that the executable responds with a result from stdout )

---

Given the clarification,

for /f "tokens=1*delims== " %%r in ('%x%') do if "%%r"=="Version" set "return=%%s"
echo %return%