c ++如何初始化数组的const元素

Question

i need a way to initialize const elements of an array for the program i am currently working on. The problem is that i have to initialize these elements with a function, there is no way to do it like this:

const int array[255] = {1, 1278632, 188, ...};

because its alot of data i have to generate. What i tried is to memcpy data to the const int's but that can't work and hasn't worked.

 const int array[255];

 void generateData(){
      for(int i = 0; i < 255; i++) {
          initializeSomehowTo(5, array[i]);
      }
 }

I hope you understand what i am trying, sorry if i doubled the question, i must have overlooked it.

Answer 1

How about this?

#include <array>
typedef std::array<int, 255> Array;

const Array array = generateData();

Array generateData(){
    Array a;
    for(int i = 0; i < a.size(); i++) {
        initializeSomehowTo(a[i]);
    }
    return a;
}

Answer 2

The easiest approach is to get the filled array from a function and use that to initialize your const (or constexpr ) object. However, built-in arrays can't be copied but std::array<T, N> be:

std::array<T, 255> array = initializeData();

If you need a built-in array, I can imagine initializing a static member of a class (template, actually) where the index is expanded from indices expanded from an std::make_index_sequence<255> and used as positional argument in the array, ie, something along these lines:

#include <algorithm>
#include <iostream>
#include <iterator>
#include <utility>

int some_function(std::size_t i) { return i; }

template <typename> struct initialized_array_base;
template <std::size_t... I>
struct initialized_array_base<std::index_sequence<I...>> {
    static const int array[sizeof...(I)];
};

template <std::size_t... I>
int const initialized_array_base<std::index_sequence<I...>>::array[sizeof...(I)]
    = { some_function(I)... };

struct initialized_array
    :initialized_array_base<std::make_index_sequence<256>> {
};

int main() {
    std::copy(std::begin(initialized_array::array),
              std::end(initialized_array::array),
              std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
}

Answer 3

You can create a writable array, initialize it, and, then, create a const reference to it.

int arry[255];

void generateData(){
  for(int i = 0; i < 255; i++) {
      initializeSomehowTo(5, arry[i]);
  }
}

const int (&array)[255] = arry;