使用whereIn（laravel 5.3）为foreach（）laravel提供的参数无效

Question

I am getting ids using jquery in my controller its as

if(!empty($request->input('ids'))) {
    $ids = $request->input('ids');
    }else{
                $ids = null;
            }

I try dd($ids)

Output is as in my console

array:3 [
  0 => "1"
  1 => "2"
  2 => "on"
]

When i pass ids to my query as

Query

$student_ids = DB::table('students')
             ->orderBy('name', 'asc')
              ->where('group_id', '<>', 0)
              ->whereIn('students.id','=', $ids)
              ->pluck('id');

Its not working

Error is : Invalid argument supplied for foreach

Please help where I am wrong. Thanks

Answer 1

You should change this:

->whereIn('students.id','=', $ids)

To this:

->whereIn('students.id', $ids)

Because the second parameter should be iterable of IDs, but you're passing a string = . Also, make sure, you're passing an array or collection of IDs.

Answer 2

Change:

where('students.id', '=', $ids)

To:

whereIn('students.id', $ids);

Answer 3

Like others have mentioned update the whereIn parameter. Also simplify your request input like so.

$ids = $request->input('ids', []);

$student_ids = DB::table('students')
    ->orderBy('name', 'asc')
    ->where('group_id', '<>', 0)
    ->whereIn('students.id', $ids)
    ->pluck('id');