[英]Replacing column values in R
Example df: df示例:
index name V1 V2 etc
1 x 2 1
2 y 1 2
3 z 3 4
4 w 4 3
I would like to replace values in columns V1 and V2 with related values in name column for particular index value. 我想用名称列中的相关值替换特定索引值的V1和V2列中的值。 Output should look like this: 输出应如下所示:
index name V1 V2 etc
1 x y x
2 y x y
3 z z w
4 w w z
I have tried multiple merge statements in loop but not sure how I can replace the values instead of creating new columns and also got a duplicate name error. 我在循环中尝试了多个merge语句,但不确定如何替换值而不是创建新列,并且还出现重复的名称错误。
V<-2 # number of V columns
names<-c()
for (i in 1:k){names[[i]]<-paste0('V',i)}
lookup_table<-df[,c('index','name'),drop=FALSE] # it's at unique index level
for(col in names){
df<- merge(df,lookup_table,by.x=col,by.y="index",all.x = TRUE)
}
We can do 我们可以做的
df[3:4] <- lapply(df[3:4], function(x) df$name[x])
Or without looping 还是不循环
df[3:4] <- df$name[as.matrix(df[3:4])]
df
# index name V1 V2
#1 1 x y x
#2 2 y x y
#3 3 z z w
#4 4 w w z
df <- structure(list(index = 1:4, name = c("x", "y", "z", "w"), V1 = c(2L,
1L, 3L, 4L), V2 = c(1L, 2L, 4L, 3L)), .Names = c("index", "name",
"V1", "V2"), class = "data.frame", row.names = c(NA, -4L))
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