在sqlite3中创建表时出错

Question

I am learning sqlite3 in python3. I have added 4 columns in my table using the syntax

c.execute("CREATE table raman(ATOMIC NUMBER INT, SYMBOL TEXT, ROW INT , COLUMN INT)")     

and I want to insert values for them so I am writing

c.execute("INSERT INTO raman VALUES(1,'H',1,'1')");      

After this if I print the table its not showing me the inserted values. I am using this command to print print c.execute("SELECT * FROM SQLITE_ master type='table'").fetchall()

Answer 1

The complete (minimal) sequence is this.

>>> conn = sqlite3.connect(':memory:')
>>> c = conn.cursor()
>>> c.execute("CREATE table raman(ATOMIC NUMBER INT, SYMBOL TEXT, ROW INT , COLUMN INT)")
<sqlite3.Cursor object at 0x000000000296E490>
>>> c.execute("INSERT INTO raman VALUES(1,'H',1,'1')"); 
<sqlite3.Cursor object at 0x000000000296E490>
>>> conn.commit()
>>> for row in c.execute('SELECT * FROM raman'):
...     row
... 
(1, 'H', 1, 1)

Until you issue the commit the values won't be (or won't necessarily be) present in the table.