[英]Why can I pass a list of named arguments — but not unnamed arguments — to this decorator?
This question is not a duplicate of How pass unknown list of unnamed arguments to a python decorator? 这个问题不是“ 如何将未知的未命名参数列表传递给python装饰器?”的重复项。 . 。 I'm asking a different but related question here. 我在这里问一个不同但相关的问题。
I have created a python decorator my_decorator
method as shown below. 我创建了一个python装饰器my_decorator
方法,如下所示。 I want this decorator to accept an unknown list of arguments: 我希望这个装饰器接受未知的参数列表:
#!/usr/bin/env python
from functools import wraps
class A:
def my_decorator(self, func=None, *args, **kwargs):
print "Hello World2!"
print 'args = {}'.format(args)
print 'kwargs = {}'.format(kwargs)
def inner_function(decorated_function):
def wrapped_func(*fargs, **fkwargs):
print "Hello World3!"
return decorated_function(*fargs, **fkwargs)
return wrapped_func
if func:
return inner_function(func)
else:
return inner_function
class B:
my_a = A()
@my_a.my_decorator(a1="Yolo", b1="Bolo")
def my_func(self):
print "Hello World1!"
my_B = B()
my_B.my_func()
This code works perfectly fine: 这段代码可以正常工作:
Hello World2!
args = ()
kwargs = {'a1': 'Yolo', 'b1': 'Bolo'}
Hello World3!
Hello World1!
However, now, instead of passing named arguments to @my_a.my_decorator
, I want to pass unnamed arguments like this: @my_a.my_decorator('Yolo', 'Bolo')
and it fails: 但是,现在,我不是将命名参数传递给@my_a.my_decorator
,而是要传递这样的未命名参数: @my_a.my_decorator('Yolo', 'Bolo')
并且它失败了:
Hello World2!
args = ('Bolo',)
kwargs = {}
Hello World3!
Traceback (most recent call last):
File "./decorator_test.py", line 20, in <module>
class B:
File "./decorator_test.py", line 23, in B
@my_a.my_decorator('Yolo', 'Bolo')
File "./decorator_test.py", line 12, in wrapped_func
return decorated_function(*fargs, **fkwargs)
TypeError: 'str' object is not callable
How can I fix this? 我怎样才能解决这个问题?
def my_decorator(self, *args, **kwargs):
[skip]
if 'func' in kwargs:
return inner_function(kwargs.pop('func'))
else:
return inner_function
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