从字符串末尾删除特定字符之后的字符串部分

Question

I need to remove all characters from a string after a particular character from the end. The below code works when it contains only one # eg:

$variable = "8233 Station #2212";
echo trim(substr($variable, 0, strpos($variable, "#")));

result: "8233 Station"; But if the string contains more than one # I need to avoid the strings after the last #

 $variable = "8233 Station #2211 #2212";

The result i need in the above situation is "8233 Station #2211"

Answer 1

Use strrpos to get position of last matching element

//$variable = "8233 Station #2212"; //8233 Station
$variable = "8233 Station #2211 #2212";
echo trim(substr($variable, 0, strrpos($variable, "#"))); //8233 Station #2211

Answer 2

It can also be done with substr() which extract the string from a string and strrpos() which return last occurrence of a character, try like below:

<?php
$variable = "8233 Station #2211 #2212";
echo substr($variable, 0, strrpos($variable, "#"));

check the output here: https://eval.in/813032

Answer 3

Use strrpos instead of strpos

strpos — Find the position of the first occurrence of a substring in a string

strrpos — Find the position of the last occurrence of a substring in a string

$variable = "8233 Station #2212 #2212";
echo trim(substr($variable, 0, strrpos($variable, "#")));