[英]Replacing specific characters in python string
I have a string which is 我有一个字符串是
string = "create (:TestCustomer {'FIRSTNAME': 'James', 'LASTNAME': 'Comey', 'CITY': 'Sydney'})"
I want to replace specific set of '
to %
. 我想将特定的
'
替换为%
。 It has to look like 它必须看起来像
string = "create (:TestCustomer {%FIRSTNAME%: 'James', %LASTNAME%: 'Comey', %CITY%: 'Sydney'})"
I'm trying to use replace function. 我正在尝试使用替换功能。 But failed to get the exact result.
但是未能获得确切的结果。
Use re
to replace patterns. 使用
re
替换模式。
>>> import re
>>> s = "create (:TestCustomer {'FIRSTNAME': 'James', 'LASTNAME': 'Comey', 'CITY': 'Sydney'})"
>>> S=re.sub(r"\'([A-Z]*)\'",r"%\1%",s)
create (:TestCustomer {%FIRSTNAME%: 'James', %LASTNAME%: 'Comey', %CITY%: 'Sydney'})
string = "create (:TestCustomer {'FIRSTNAME': 'James', 'LASTNAME': 'Comey', 'CITY': 'Sydney'})"
w = string.find('{')+ 1
x = w + 10;t = w + 22;y = w + 31;z = w + 43;q = w + 48
w1=string[w].replace("'",'%')
x1=string[x].replace("'",'%')
t1=string[t].replace("'",'%')
y1=string[y].replace("'",'%')
z1=string[z].replace("'",'%')
q1=string[q].replace("'",'%')
print(string[0:23]+w1+string[24:33]+x1+string[34:45]+t1+string[46:54]+y1+string[55:66]+z1+string[67:71]+q1+string[72:])
hope that is what you wanted. 希望那是你想要的。
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