从视图传递jquery var到codeigniter中的控制器

Question

This is in script .ready() function which fetch existing files from database and putting in jquery var splitfiles . which is in array formate.

  var splitfiles = '<?php echo @$projectDetails->upload_file; ?>'; 

this line gives array of attached file from view in controller

 $arrayoffiles = json_encode($joinfiles);

I want to get this splitfiles var in controller and then merge with $arrayoffiles after that store in database with other form data.

I tried with this solution to pass 'splitfiles' to controller by this bellow code but i am not getting in the controller

 $(document).ready(function() {
    $.ajax({
    url: '<?php echo site_url("trusts/fundsRaisingModule"); ?>',                       
    type: 'GET',  
    dataType: 'json',   

    data: {
        splitfiles:splitfiles,
        // key : value pair. You can send as many pair as you want like this
    }

   });
 });

In controller i am not getting the 'splitfiles'

    $files=$_REQUEST['splitfiles'];

giving error :undefined index 'splitfiles' so help me to pass jquery variable from view to controller in codeigniter after that i will try to merge the two arrays Thanks in advance.

Answer 1

To achieve this use jquery ajax() and send the js variable to controller method and use it as you want.

Its syntax is:

$(document).ready(function(){
    $.ajax({
        url: 'controller_method',                        
        type: 'POST',                                  
        data: {
            splitfiles  :splitfiles,
            // key : value pair. You can send as many pair as you want like this
        },
        success: function(response){    // response from process
            // do your stuff here
        }
    });
});

controller_method

$splitfiles = $_REQUEST['splitfiles'];
// do your stuff here

Note: Don't forget to add the jquery library in your code.

Answer 2

首先将该jQuery变量发送到视图的任何隐藏输入中，然后通过GET或POST方法将该输入值获取到控制器中。