[英]python ZEEP: GUID not parsed from XML to JSON in SOAP response
I am connecting to a SOAP web service using the ZEEP library for python and found that one of the fields that is returned in the XML is not parsed correctly. 我正在使用ZEEP库(用于python)连接到SOAP Web服务,发现未正确解析XML中返回的字段之一。 I have copied the fragment from the XML response below, as well as the parsed JSON. 我已经从下面的XML响应以及已解析的JSON复制了片段。
Also refer to https://gist.github.com/bsteverink/dede1f3341828d069a502f16ccc5da0b for the full demonstration as per instruction in the ZEEP documentation. 另请参阅https://gist.github.com/bsteverink/dede1f3341828d069a502f16ccc5da0b ,以获取ZEEP文档中的完整演示。
I am using Zeep 2.0.0. 我正在使用Zeep 2.0.0。
The fragment that is returned from the SOAP service: 从SOAP服务返回的片段:
<GetDataExchangeQueryResultRow>
<DataType>System.Guid</DataType>
<ReturnObject xmlns:q1="http://microsoft.com/wsdl/types/" xsi:type="q1:guid">16fed64c-9b6d-4383-bdd1-fd5cde084afe</ReturnObject>
<DisplayName>Auto_ID</DisplayName>
</GetDataExchangeQueryResultRow>
The JSON result from the client: 客户端的JSON结果:
{
'DataType': 'System.Guid',
'ReturnObject': [],
'DisplayName': 'Auto_ID'
}
Any tips, hints would be welcome. 任何提示,提示都将受到欢迎。
该库的作者指出,我需要将该库更新为github master。
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