我可以在 JpaRepository nativeQuery 中使用枚举参数吗？

Question

Entity looks like this:

@Getter
@Setter
@Entity
public class Application {
@Id
private Long id;
@Enumerated(EnumType.STRING)
private ApplicationStatus status;
}

Code works this way:

public interface ApplicationRepository extends JpaRepository<Application, Long> {
@Query("SELECT app FROM #{#entityName} AS app WHERE app.status LIKE :status")
List<Application> find(@Param("status") ApplicationStatus status);

But the same snippet with nativeQuery - doesn't:

@Query(value = "SELECT app.* FROM application AS app WHERE app.status LIKE :status", nativeQuery = true)
List<Application> findNative(@Param("status") ApplicationStatus status);
}

And I don`t have any exception, just empty list.

How can I fix this? Is it possible to use enum with nativeQuery ?

PS I can pass String into method instead of ApplicationStatus but maybe there are another option?

Answer 1

Following similar question with similar requirement and one of the answers pointing to Spring Expression Language (SpEL) you could use:

public interface ApplicationRepository extends JpaRepository<Application, Long> {
    @Query(nativeQuery = true, value = "SELECT app FROM #{#entityName} AS app WHERE app.status=:#{#status.name()}")
    List<Application> find(@Param("status") ApplicationStatus status);
}

Above important part is app.status=:#{#status.name()}

Answer 2

To extend @Aivaras answer: If you want to use list of statuses, SpEL ecpression is slightly different - you need to do projection:

public interface ApplicationRepository extends JpaRepository<Application, Long> {
    @Query(nativeQuery = true, value = "SELECT app FROM #{#entityName} AS app WHERE app.status in :#{#statuses.![name()]}")
    List<Application> find(@Param("statuses") List<ApplicationStatus> statuses);
}

Note the change of expression to

#{#statuses.![name()]}

Answer 3

您可以在传递参数之前转换为字符串。

Answer 4

how about this?

public interface ApplicationRepository extends JpaRepository<Application, Long> {
List<Application> findByStatus(ApplicationStatus status);

Answer 5

After a few days with this error, I was able to find the solution.

I did a lot of research and tested in many ways receiving as a parameter @Param("environment") environment: Environment :

 :#{#environment.TESTING}
 :#{#environment}
 :#{#environment.name()}
 CAST(:#{#environment.name()} as environment)

---

Solution in Kotlin

The key is in the query. You must to transform the value of the parameter to a String using .name() (or receive a String as a parameter) and cast that value of type String to the specific Enum that is needed . Because passing an object of type Enum directly in the query does not work.

Assuming the Enum in your database is defined as environment .

@Query(
        value = "SELECT some_routine(CAST(:#{#environmentNamedParam.name()} as environment))",
        nativeQuery = true
)
fun yourFunction(
        @Param("environmentNamedParam") environmentParam: Environment
) : Boolean

Differentiate between:

• environmentNamedParam
• environmentParam
• environment

---

#spring #jpa #postgresql #kotlin

Answer 6

I solved this issue using #{#paramName?.name()}

public interface ItemRepository extends JpaRepository<Item, Long> {
    @Query(value = "select * from items where type = :#{#type?.name()}", nativeQuery = true)
    List<Item> findByType(@Param("type") EnumType type);
}
 
public enum EnumType { NORMAL, LARGE };